SyntaxFlow

Envelope · Thermal

Whole-house heat loss

A house needs exactly as much heat as it leaks, and it leaks through three things: surfaces, junctions and air. Add up the area of every surface times its U-value, add an allowance for the junctions between them, add the air that leaves and has to be reheated, and multiply the lot by how cold it gets. That number — in kilowatts — is what the boiler or the heat pump has to cover on the worst day of the year. It is almost always far smaller than the one on the appliance already installed.

The house
Volume is internal floor area × storey height, all storeys. If you only know the area, multiply by about 2.5 m.
Conditions
The design outside temperature is not the record low — it is the temperature the local climate falls below only a few days a year. Roughly −2 °C for maritime north-west Europe, −10 to −16 °C inland and continental, +2 to −2 °C around the Mediterranean.
Only used for the annual estimate. Mild maritime climates run about 1500–2200, continental ones 2800–3800, southern Mediterranean 900–1500. If your figure is a US-style HDD65 (base 18 °C) it will read high here — see the notes.
The fabric
ElementU
Each row is an element: what it is, then its area in m² and its U-value.
Areas are measured externally, wall to wall, with no deduction where one element meets another. Window area comes out of the wall area, not on top of it. Don't know a U-value? Work it out with the wall and roof calculator or the window one.
Junctions and air
This multiplies the total envelope area, so it quietly becomes one of the biggest lines. Calculate it properly instead of guessing.
Leaky older house 0.8–1.5 ach, average 0.4–0.7, airtight new build 0.1–0.2. Heat recovery never touches the air that leaks through gaps — that is the whole reason airtightness has to come first.
Design heat load
kW
Per m² of floor
W/m²
Heat loss coefficient
W/K
Annual heat demand
kWh/yr

The whole calculation

There is no cleverness in it. The care is all in the inputs.

fabric H_fab = Σ ( A · U · b ) // b = 1 external, 0.5 unheated space, 0.45 ground junctions H_tb = y · Σ A // y multiplies the TOTAL envelope area air H_ven = 0.33 · V · ( n_inf + n_mech · (1 − η) ) total H = H_fab + H_tb + H_ven // watts per kelvin design load Φ = H · ( θ_int − θ_ext ) // watts, the worst-day number annual Q = H · DD · 24 / 1000 // kWh/year, degree-day estimate

The 0.33 is the heat capacity of air in convenient units: 1.2 kg/m³ × 1005 J/(kg·K) works out at 0.33 watt-hours per cubic metre per kelvin. So one air change an hour in a 250 m³ house costs 82 watts for every degree of temperature difference, whatever the walls are made of.

What the answer is for

What the number should look like

Design heat loadWhat that means
≤ 10 W/m²Passivhaus territory. The building can be heated through the ventilation air alone.
10 – 30Very good. A small heat pump at low flow temperature, comfortably.
30 – 50A decently insulated house. Heat pump works, emitters may need enlarging.
50 – 80Insulated in places. Fabric work pays back before plant does.
> 80Largely uninsulated. Sizing plant for this is treating the symptom.

Compare that with the rule of thumb still used to sell boilers — around 100 W/m², or "one kilowatt per room" — and you can see why so much plant is two or three times too big. An oversized boiler cycles, an oversized heat pump cycles harder and costs more to buy.

Worked example you can check by hand

The house this page opens with: 100 m² floor, 250 m³, 21 °C inside, −2 °C outside.

walls 90 m² × 0.30 × 1.00 = 27.000 W/K roof 55 m² × 0.16 × 1.00 = 8.800 ground fl. 55 m² × 0.25 × 0.45 = 6.188 windows 18 m² × 1.40 × 1.00 = 25.200 doors 4 m² × 1.80 × 1.00 = 7.200 H_fab = 74.388 junctions 0.08 × 222 m² = 17.760 air 0.33 × 250 × 0.5 = 41.250 H = 133.397 W/K Φ = 133.397 × 23 K = 3068 W = 3.07 kW per m² of floor = 30.7 W/m² Q = 133.397 × 2000 × 24 / 1000 = 6403 kWh/yr

And the part that catches people out: the ventilation is 41.3 W/K, the single largest line on the sheet — bigger than all the walls put together, and two and a half times the roof and floor combined. Halve the leakage and the house needs 2.59 kW instead of 3.07, which is a whole heat-pump size. Insulating the walls from 0.30 to 0.18 saves less than that, and costs twenty times as much.

What this page does not do

Read this. This is a screening calculation for understanding a building and checking whether a quoted plant size is sane. Sizing equipment that someone will live with needs a room-by-room load to EN 12831 with real local design data, and a measured air test rather than an assumed air change rate.