Building envelope · Heating
Radiator size calculator
A radiator rated at ΔT50 gives less with cooler water: output = rating × (ΔT / 50)^1.3. For a room that loses 1,200 W, a heat pump at 45/40 °C needs 3,595 W (12,265 BTU/h) of radiator at ΔT50; a boiler at 75/65 °C, 1,232 W. Radiators are sold by their ΔT50 output, so that is the figure to compare in a catalogue.
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Radiator to buy, ΔT50
— W
Mean water to room
— K
Existing radiators give
— W
Room heat loss
— BTU/h
How radiator output changes with water temperature
ΔT = (flow + return) / 2 − room
output = ΔT50 rating × (ΔT / 50)^n n ≈ 1.3 (EN 442)
rating needed = room heat loss × (50 / ΔT)^n
A heat pump at 45/40 °C with the room at 21 °C has a mean water temperature of 42.5 °C, so ΔT = 21.5 K, and (50 / 21.5)^1.3 = 3.00: the radiator has to be rated about 3.0 times the room’s heat loss. At 75/65 °C, ΔT = 49 K and the factor is 1.03.
Output of a radiator by flow and return temperature
| Flow / return | ΔT (K), room 21 °C | Share of ΔT50 output | ΔT50 rating for 1,000 W |
|---|---|---|---|
| 75 / 65 °C | 49.0 | 0.97 | 1,027 |
| 70 / 60 °C | 44.0 | 0.85 | 1,181 |
| 60 / 50 °C | 34.0 | 0.61 | 1,651 |
| 55 / 45 °C | 29.0 | 0.49 | 2,030 |
| 50 / 45 °C | 26.5 | 0.44 | 2,283 |
| 45 / 40 °C | 21.5 | 0.33 | 2,996 |
| 40 / 35 °C | 16.5 | 0.24 | 4,226 |
| 35 / 30 °C | 11.5 | 0.15 | 6,757 |
Arithmetic mean ΔT, as radiator makers’ tables use, and n = 1.3. With a very small temperature difference the logarithmic mean of EN 442 gives a little less.
What this page does not do
- It does not work out the heat loss. That comes from the walls, windows, floor, roof and air change of each room: the heat loss calculator does it, and the average heat loss of a house page gives the heat pump size for the whole house.
- It does not design the system. Pipe sizes, flow rates and the heat pump’s own curve are for the installer; a heat pump survey (MCS in the UK) sizes them room by room.
Questions people ask
- How do I calculate what size radiator I need?
- Work out the room's heat loss in watts, then multiply by (50 / ΔT)^1.3, ΔT being the mean water temperature minus the room's. For 1,200 W with a boiler at 75/65 °C that is 1,232 W of radiator at ΔT50.
- What size radiator do I need for a heat pump?
- About 3.0 times the room's heat loss at 45/40 °C flow and return with the room at 21 °C: (50 / 21.5)^1.3 = 3.00. A room losing 1,200 W needs 3,595 W at ΔT50.
- How much heat does a radiator give at a lower flow temperature?
- Its ΔT50 rating × (ΔT / 50)^1.3. A 1,500 W radiator gives 501 W at 45/40 °C with the room at 21 °C, 33 % of its rating.
- How many BTU is a watt?
- 1 W = 3.412 BTU per hour, so a 1,000 W radiator is 3,412 BTU/h.
- What does ΔT50 mean on a radiator?
- That the output is measured with the mean water temperature 50 K above the room, for example 75 °C flow, 65 °C return and a 20 °C room (EN 442). It is the figure radiators are sold by.